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II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\

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Last updated 24 Sept 2024
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\theta]=+\cos \theta \\ \cos [90+\theta]=-\sin \theta \\ \tan [90+\theta]=-\cot \theta \\ \cot [90+\theta]=-\tan \theta \end{array} \]
Video solution 1: II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\theta]=+\cos \theta \\ \cos [90+\theta]=-\sin \theta \\ \tan [90+\theta]=-\cot \theta \\ \cot [90+\theta]=-\tan \theta \end{array} \]
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
sin(90-θ)=?
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
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II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
19. [cos(90-θ) sec(90-θ) tanθ/cosec(90-θ) sin(90-θ) cot(90-θ)] +
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
How to get values for sin (90° - θ), cos (90° - θ), sin (90° + θ
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
Solved 14.9 Prove that for R(θ)=(cosθsinθ−sinθcosθ) the
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
Solved L.H.S. =cos(90∘−θ)=sinθ∵ L.H.S. = R.H.S.
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
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II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
cos(90−θ)sec(90−θ)tanθ/cosec (90−θ)sin(90−θ)cot(90−θ)+tan(90
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
sin(90-θ)=?
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
sin{ 22 }^{ circ }cosec({ 90 }^{ circ }-theta )=1, Find theta .
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
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II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
Solved
II cordnent [sinθ×cosecθ+4e] [90+θ) \[ \begin{array}{l} \sin [90+\
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